Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q261. | Price of a commodity is increased by 30%. By what % consumption will get change if expenditure is also increased by 17% ? |
| 1) | 7% | 2) | 10% |
| 3) | 13% | 4) | 17% |
| 5) | None of these | ||
Answer : 10%
Explanation : Let, the original price of the commodity be Rs.100/.
Explanation : Let, the original price of the commodity be Rs.100/.
After 20% increase, the new price became Rs.130/.
Expenditure only increase 17%.
so, Actual % of change in expenditure = [ (130-117)/130 ] x 100 = 10%
View AnswerQ262. |
|
| 1) | 15% | 2) | 18% |
| 3) | 20% | 4) | 25% |
| 5) | None of these | ||
Answer : 20%
Explanation :
Explanation :
Let, the C.P. of 100 ltr of milk is Rs 100
Therefore , the SP also of 100 ltr mixture (milk+water) will be Rs 100, where gain is 25%
So the C.P. of 100 ltr of mixture = (100/125)*100 =Rs 80/
Hence the gain = 100 - 80 = Rs.20
So the gain in percentage = 20%
Hence, the percentage of water in the milk = 20%
View AnswerQ263. |
|
| 1) | Rs.6000 | 2) | Rs.7500 |
| 3) | Rs.8000 | 4) | Rs.10,000 |
| 5) | None of these | ||
Answer : Rs.8000
Explanation :
Explanation :
Let, the labelled price be Rs.100, S.P in Ist case = Rs.80, S.P in 2nd case = Rs.75.
If saving is Rs.5,
So, labelled price = Rs.[(500/5)x80] = Rs.8000
View AnswerQ264. |
|
| 1) | 36:51 | 2) | 45 : 56 |
| 3) | 50 : 81 | 4) | 56:45 |
| 5) | None of these | ||
Answer : 45 : 56
Explanation :
Explanation :
Let, the printed price of the book be Rs.100. After a discount of 10% S.P= Rs.90 Profit earned = 12%
C.P. of the book =
Rs. [100/112×90] = Rs.1125/14
Hence, (C.P) : (printed price)=1125/14:100 or 45:56
View AnswerQ265. | A man bought a number of oranges at 3 for a rupee and an equal number at 2 for a rupee. At what price per dozen should he sell them to make a profit of 20 % ? |
| 1) | 4 | 2) | 6 |
| 3) | 8 | 4) | 12 |
| 5) | None of these | ||
Answer : 6
Explanation : The CP of one orange = 1/3 and another CP of 2 oranges = 1/2, then 2 oranges = 5/6
Explanation : The CP of one orange = 1/3 and another CP of 2 oranges = 1/2, then 2 oranges = 5/6
Then 1 oranges = 5/12
So,12 * 5/12 * 120/100 = 6
View AnswerQ266. | A article is sold at 10% discount on its marked price of Rs. 480. If the retailer makes 20% profit on the cost price, what should be the cost price of the article? |
| 1) | Rs.300 | 2) | Rs.320 |
| 3) | Rs.360 | 4) | Rs.400 |
| 5) | None of these | ||
Answer : Rs.360
Explanation : If marked price is Rs. 100, selling price = 100 - 10 = Rs. 90
If cost price is Rs. 100, selling price = 100 + 20 = Rs. 120
Therefore, Cost price = 480 x (90/100) x 100/120 = 360
Explanation : If marked price is Rs. 100, selling price = 100 - 10 = Rs. 90
If cost price is Rs. 100, selling price = 100 + 20 = Rs. 120
Therefore, Cost price = 480 x (90/100) x 100/120 = 360
View AnswerQ267. | By selling 90 ball pens for Rs 160, a person loses 20%. How many ball pens should he sell for Rs 96, so as to have a gain of 20% ? |
| 1) | 25 | 2) | 30 |
| 3) | 36 | 4) | 37 |
| 5) | None of these | ||
Answer : 36
Explanation : Given, selling 90 ball pens for Rs 160, lose is 20%.
Explanation : Given, selling 90 ball pens for Rs 160, lose is 20%.
So, C.P of 90 ball pen = [(160/80) x 100 ] /90 = 200/90
C.P of 96 ball pens = (200/90) x 96
C.P of 1 ball pen = 96 x (90/200)
To have a gain of 20%, the number of ball pens should be sell for Rs. 96 = 96 x (90/200) x 100/120 = 36
View AnswerQ268. | There are 5 professors from IIT Delhi and 3 professors from IIT Bombay who are sitting together to discuss a matter at a round table. In how many ways can they sit around the table so that no two professors from IIT Bombay are together ? |
| 1) | 600 | 2) | 840 |
| 3) | 1200 | 4) | 1440 |
| 5) | None of these | ||
Answer : 1440
Explanation : Given, no professors of IIT-B together. Suppose, we first arrange 5 prof. IIT-D and after that we can arrange the IIT-B in space between IIT-D.
Explanation : Given, no professors of IIT-B together. Suppose, we first arrange 5 prof. IIT-D and after that we can arrange the IIT-B in space between IIT-D.
So, numbers of way of arranging the IIT-Bin the circle = (5-1)! = 24 ways.
Numbers of way of arranging IIT-B will be by placing them in 5 space that are formed between the IIT-D.
This can be arranged in 5p3 = 60 ways.
therefore, total number of ways = 24 x 60 =1440
View AnswerQ269. |
|
| 1) | 196 | 2) | 630 |
| 3) | 1260 | 4) | 2520 |
| 5) | None of these | ||
Answer : 630
Explanation :
Explanation :
L.C.M. of 12, 18, 21 30
= 1260.
So, required number = (1260 ÷ 2) = 630.
View AnswerQ270. |
|
| 1) | 1677 | 2) | 1683 |
| 3) | 2523 | 4) | 3363 |
| 5) | None of these | ||
Answer : 1683
Explanation :
Explanation :
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
View Answer