Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
| Q241. | 
 | 
| 1) | 2:3 | 2) | 4:5 | 
| 3) | 3:4 | 4) | 6:7 | 
| 5) | None of these | ||
Answer : 2:3 
Explanation : Given,

Explanation : Given,

 View Answer
 View Answer| Q242. | 
 | 
| 1) | Rs.17,000 | 2) | Rs.20,000 | 
| 3) | Rs.25,500 | 4) | Rs.38,000 | 
| 5) | None of these | ||
Answer : Rs.38,000	 
Explanation :

Explanation :

 View Answer
 View Answer| Q243. | 
 | 
| 1) | 20 litres | 2) | 30 litres | 
| 3) | 40 litres | 4) | 60 litres | 
| 5) | None of these | ||
Answer : 60 litres 
Explanation :

Explanation :

 View Answer
 View Answer| Q244. | 
 | 
| 1) | 2 : 5 | 2) | 3 : 5 | 
| 3) | 4 : 5 | 4) | 6 : 7 | 
| 5) | None of these | ||
Answer : 4 : 5 
Explanation :

Explanation :

 View Answer
 View Answer| Q245. | 
 | 
| 1) | 24 | 2) | 38 | 
| 3) | 42 | 4) | 48 | 
| 5) | Non of these | ||
Answer : 38 
Explanation :
Explanation :
	Let, the numbers be x and x + 2.
	Then, (x + 2)2 - x2 = 84
	or 4x + 4 = 84    or  4x = 80
	or x = 20. The required sum = x + (x + 2) = 2x + 2 = 42.
 View Answer
 View Answer| Q246. | 
 | 
| 1) | 235 | 2) | 253 | 
| 3) | 273 | 4) | 352 | 
| 5) | None of these | ||
Answer : 253 
Explanation :
Explanation :
Let, the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred's digits is smaller than the unit's digit.
Hence, required number = 253.
 View Answer
 View Answer| Q247. | 
 | 
| 1) | 18 | 2) | 24 | 
| 3) | 42 | 4) | 81 | 
| 5) | None of these | ||
Answer : 24 
Explanation :
Explanation :
Let, the ten's and unit digit be x and y	respectively.
So, xy = 8 and the number be 10x+y
When 18 is added,  the number be 10x+ y +18.
Then, 10x + y + 18 = 10 y + x
or 9x - 9y = -18   x - y = - 2
 We know that (x+y)2=( x-y)2 + 4xy = (-2)2 + 4 x 8 =36
or x+y = 6
By solving we get x = 2 and  y = 4
Thus, the number is 24.
 View Answer
 View Answer| Q248. | 
 | 
| 1) | 3 | 2) | 5 | 
| 3) | 10 | 4) | 11 | 
| 5) | None of these | ||
Answer : 11 
Explanation :
Explanation :
Let, the ten's digit be x and unit's digit be y.
	Then, number = 10x + y.
	Number obtained by interchanging the digits = 10y + x.
	(10x + y) + (10y + x) = 11(x + y), which is divisible by 11
 View Answer
 View Answer| Q249. | 
 | 
| 1) | 4 | 2) | 8 | 
| 3) | 12 | 4) | 14 | 
| 5) | None of these | ||
Answer : 8 
Explanation :
Explanation :
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let, ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36   
or 9x = 36
or x = 4.
So, required difference = (2x + x) - (2x - x) = 2x = 8.
 View Answer
 View Answer| Q250. | 
 | 
| 1) | 1 | 2) | 53 | 
| 3) | 66 | 4) | 67 | 
| 5) | None of these | ||
Answer : 66 
Explanation :
Explanation :
(xn + 1) will be divisible by (x + 1) only when n is odd.
	(6767 + 1) will be divisible by (67 + 1)
	(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
 View Answer
 View Answer
