Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
| Q231. | 
 | 
| 1) | 30% | 2) | 45% | 
| 3) | 60% | 4) | 75% | 
| 5) | None of these | ||
Answer : 45% 
Explanation : Let, total numbers of houses are 100%.
Explanation : Let, total numbers of houses are 100%.
Two or more people = 40%  and only one people = 60%
Only one male = 60 x (25/100) = 15%
So, exactly one female and no male = 60-15 = 45%
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 View Answer| Q232. | 
 | 
| 1) | 200 | 2) | 300 | 
| 3) | 400 | 4) | 480 | 
| 5) | None of these | ||
Answer : 400 
Explanation : Let, total number of student are 100%.
Explanation : Let, total number of student are 100%.
Given,  |M| = 25% and |E| = 12%  and |M ^ E| = 10% 
So, |M u E| = M| + |E|  -  |M ^ E| = (25 +12 -10) = 27%
Therefore, 100 - 27 = 73%
So, Total students = (292/73) x 100 = 400
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 View Answer| Q233. | 
 | 
| 1) | Rs.400 | 2) | Rs.432 | 
| 3) | Rs.442 | 4) | Rs.420 | 
| 5) | None of these | ||
Answer : Rs.420	 
Explanation : Let, the average expenditure of the mess per day is Rs.x.
Explanation : Let, the average expenditure of the mess per day is Rs.x.
Then, total expenditure/day = Rs.35x
Now, total students = 35+7= 42 and new expenditure of the mess =  Rs.(35x +42) 
So, Rs.(35x +42) /42 = Rs.x-1
or 35x + 42 = 42x -42 
or 7x = 84
or x = 12
Therefore, original expenditure of the mess = 35 x 12= Rs.420
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 View Answer| Q234. | 
| 1) | 3/2 | 2) | 31/2 | 
| 3) | 127/108 | 4) | 121/108 | 
| 5) | None of these | ||
Answer : 121/108 
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 View Answer| Q235. | 
| 1) | 0 | 2) | 1 | 
| 3) | 2 | 4) | 3 | 
| 5) | None of these | ||
Answer : 0 
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 View Answer| Q236. | What is  | 
| 1) | 2 | 2) | 3 | 
| 3) | 4 | 4) | 5 | 
| 5) | None of these | ||
Answer : 3 
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 View Answer| Q237. | 
| 1) | 3/7 | 2) | 1 | 
| 3) | 2 | 4) | 4 | 
| 5) | None of these | ||
Answer : 1 
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 View Answer| Q238. | 16 men can complete a piece of work in 8 days. 20 women take 16 days to complete the same piece of work. 12 men and 10 women work together for 6 days. How many more days would 10 women alone require to complete the remaining piece of work ? | 
| 1) | 6 days | 2) | 8 days | 
| 3) | 10 days | 4) | 12 days | 
| 5) | None of these | ||
Answer : 8 days 
Explanation : Given,16 men can complete a piece of work in 8 days while 20 women take 16 days to complete the same piece of work.
Explanation : Given,16 men can complete a piece of work in 8 days while 20 women take 16 days to complete the same piece of work.
The ratio of  the capacity of doing work i.e. men to women = (20 x 16 ) : (16 x 8) = 5:2
So, 1 man = 2.5 women
Now, 12m + 10w = (12 x 2.5) = 40w
Given, 20 women take 16 days to complete the same piece of work.
Given, 20 women take 16 days to complete the same piece of work.
1 woman can do it in = 16 x 20 = 320 days i.e. 1/320 parts in 1 day.
40 women can do in 6 days = (1/320) x 40 x 6 = 6/8 = 3/4 parts
Therefore, remaining 1-3/4=1/4 part of the work done by only 10 women in = 
Applying Chain Rule:
 M1 x D1 x W2 = M2 x D2 x W1
or 20w x16 x 1/4 = 10w x D2 x 1 
or D2  = 8 days
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 View Answer| Q239. | 
 | 
| 1) | 20 | 2) | 30 | 
| 3) | 48 | 4) | 58 | 
| 5) | None of these | ||
Answer : 30 
Explanation :

Explanation :

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 View Answer| Q240. | 
 | 
| 1) | 20 | 2) | 30 | 
| 3) | 48 | 4) | 58 | 
| 5) | None of these | ||
Answer : 30 
Explanation :

Explanation :

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