Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q441. |
Directions: Study the following bar Graph carefully and answer the questions given bellow : The Bar Graph shows the percentage of three communities - A, Community B and Community C in a state during the years from 2004 to 2007.  If the total population in 2004 was 8,00,000 and in 2006 it was 9,00,000, by how much has the population of Community B increased in 2 years? |
| 1) | 25% | 2) | 50% |
| 3) | 75% | 4) | 80% |
| 5) | None of these | ||
Answer : 50%
Explanation : 45% of 800000 is 360000 and 60% of 900000 is 540000
Explanation : 45% of 800000 is 360000 and 60% of 900000 is 540000
So, the percentage of population increases = [(540000 - 360000)/360000] x 100 = 50%
View AnswerQ442. |
Directions: Study the following bar Graph carefully and answer the questions given bellow : The Bar Graph shows the percentage of three communities - A, Community B and Community C in a state during the years from 2004 to 2007. If the total population of the state in 2005 was 6 million, then the population of Community A was Answer (b). |
| 1) | 1800000 | 2) | 1950000 |
| 3) | 2100000 | 4) | 2250000 |
| 5) | None of these | ||
Answer : 2100000
Explanation :
Explanation :
In the year 2005, the population percentage of Community A ,B and C
= (35+55+15) % = 100%
So,the total population of Community A is (6,000,000)x(35/100) = Rs.2,100,000.
View AnswerQ443. |
Directions: Study the following bar Graph carefully and answer the questions given bellow : The Bar Graph shows the percentage of three communities - A, Community B and Community C in a state during the years from 2004 to 2007. If the total population of the state in 2004 was 5 lakhs, then the combined population of Community A and Community C in that year was |
| 1) | 180000 | 2) | 200000 |
| 3) | 250000 | 4) | 275000 |
| 5) | None of these | ||
Answer : 275000
Explanation : Total population = (500000 x 55)/100 = Rs.2,75,000.
Explanation : Total population = (500000 x 55)/100 = Rs.2,75,000.
View AnswerQ444. |
|
| 1) | 1:2 | 2) | 2:3 |
| 3) | 3:4 | 4) | 3:5 |
| 5) | None of these | ||
Answer : 2:3
Explanation : Community A : Community B = 30:45 or 2 : 3.
Explanation : Community A : Community B = 30:45 or 2 : 3.
View AnswerQ445. |
Direction: read the following the bar graph given below and give the answer: The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991-92 to 1998-99. :  The foreign exchange reserves in 1996-97 were approximately what percent of the average foreign exchange reserves over the period under review ? |
| 1) | 80% | 2) | 85% |
| 3) | 90% | 4) | 125% |
| 5) | None of these | ||
Answer : 125%
Explanation :
Explanation :
The average of these 8 years =
1/8 (2640+3720+2520+3360+3120+4320+5040+3120) = US $ 3480 million
Foreign exchange reserves in 1996-97 = US $ 4320 million
So, required Percentage = [(4320/3480)x100] % = 125%
View AnswerQ446. |
Direction: read the following the bar graph given below and give the answer: The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991-92 to 1998-99. : The ratio of the number of years, in which the foreign exchange reserves are above the average reserves, to those in which the reserves are below the average is: |
| 1) | 2:5 | 2) | 3:5 |
| 3) | 3:4 | 4) | 4:7 |
| 5) | None of these | ||
Answer : 3:5
Explanation :
Explanation :
Average foreign exchange reserves over the given period is = 3480 million US $
The country had reserves above 3480 million US $ during the years 1992-93, 1996-97 and 1997-98. So three years is was above the average and for rest of five years it was below the average
So required ratio is 3:5
View AnswerQ447. |
Direction: read the following the bar graph given below and give the answer: The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991-92 to 1998-99. : FOr which year, the percent increase of foreign exchange reserves over the previous year is the highest ? |
| 1) | 1992-93 | 2) | 1994-95 |
| 3) | 1995-96 | 4) | 1998-99 |
| 5) | None of these | ||
Answer : 1992-93
Explanation :
Explanation :
Lets calculate the percentage increase of these years compared to previous years :
For year 1992-93 =(3720−2640)/2640 x100 = 40.91%
For year 1994-95 = (3360−2520) /2520 x100 = 33.33%
For year 1996-97 = (4320−3120) /3120x100 = 38.46%
For year 1997-98 = (5040−4320) /4320∗100 = 16.67%
View AnswerQ448. |
|
| 1) | 85% | 2) | 90% |
| 3) | 100% | 4) | 105% |
| 5) | None of these | ||
Answer : 100%
Explanation :
Explanation :
Foreign exchange reserve in 1997-98 = 5040 million US $
Foreign exchange reserve in 1993-94 = 2520 million US $
Increase = 5040 - 2520 = 2520 million US $
So, the percentage Increase =(2520 / 2520) x100 = 100%
View AnswerQ449. |
Direction: read the following the bar graph given below and give the answer: The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991-92 to 1998-99. : |
| 1) | 1.2 | 2) | 1.5 |
| 3) | 2.5 | 4) | 3 |
| 5) | None of these | ||
Answer : 1.5
Explanation : Required Ratio = 5040 / 3360 = 1.5
Explanation : Required Ratio = 5040 / 3360 = 1.5
View AnswerQ450. |
|
| 1) | 42 cm | 2) | 48 cm |
| 3) | 52 cm | 4) | 64 cm |
| 5) | None of these | ||
Answer : 52 cm
Explanation :
Explanation :
Let, the diagonals be PR and SQ and O is the centre ,such that PR = 24 cm and SQ = 10 cm
PO = OR = 24/2=12 cm SO = OQ = 10/2=5 cm PQ = QR = RS = SP = 122+52 =√144+25 = √169=13 cm
So, perimeter = 4 × 13 = 52 cm
View Answer