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Mathmetics

ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams

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Q461.

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age ?

1)	2 times	2)	3 times
3)	4 times	4)	5 times
5)	None of these

Answer : 2 times
Explanation :

Let, Ronit's present age be x years.

Then, father's present age = (x + 3x) years = 4x years.

(4x+8) = (x + 2) 5/2

or 8x + 16 = 5x + 40

or 3x = 24 or x = 8.

Hence, required ratio = (4x+16) / (x+16) = 48/24 =2.

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Q462.

Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 yrs. old after 10yrs. ?

1)	10 yrs	2)	12 yrs
3)	16 yrs	4)	20 yrs
5)	None of these

Answer : 20 yrs
Explanation :

Let, age of Ajaya 10 years back was x years.

Then, Sachin�s age 10yrs. was 2x yrs.

So, 2x + 20 = 40

or x = 10 yrs.

So, the present age of Ajay = 10 +10 = 20 yrs.

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Q463.

The sum of the ages of a son and his father is 56yrs. After four yrs, the age of father will be three times that of the son . Find the age of the son ?

1)	6 yrs	2)	10 yrs
3)	12 yrs	4)	20 yrs
5)	None of these

Answer : 12 yrs
Explanation :

Let the age of the son and father be x yrs. and y yrs. respectively.

Then , x + y = 56 yrs. ---- I

After 4yrs. age of both will be 56 + 8 = 64yrs.

But according to hypothesis,

or 3 (x + 4) = y + 4 or 3x + 12 = y + 4 or 3x - y = - 8 -------- II

Solving both equations, we get x = 12.

SHORT-CUT METHOD:

[64/3+1] - 4 = 12 yrs

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Q464.

The age of A's father is four times of his son. If 5 yrs ago, father's age was seven times of his son at that time. What is the present age of A's father ?

1)	28	2)	32
3)	40	4)	45
5)	None of these

Answer : 40
Explanation :

Let age of son be x.Then father's age be 4x.

Five years ago age of boths are x - 5 and 4x - 5 respectly.

or 7 (x - 5 ) = 4x - 5

or 7x - 35 = 4x - 5 or 7x - 4x = 30 or 3x = 30 or x = 10

Therefore, Father's age = 10 x 4 = 40 years

SHORT-CUT METHOD :

Father's age = [5 x(7-1)] /(4-1) x 4 = 40 yrs

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Q465.

A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:

1)	90 cm	2)	100 cm
3)	1 m	4)	1.1 cm
5)	None of these

Answer : 100 cm
Explanation :

Let the thickness of the bottom be x cm.

Then, [(330 - 10) x (260 - 10) x (110 - x)] = 8000 x 1000

or 320 x 250 x (110 - x) = (8000 x 1000)

(110 - x) = (8000 x 1000)/(320 x 250) or x = 100

So, x = 100 cm .

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Q466.

The length of a plot of land is 4 times it breadth. A playground measuring 1200 sq m occupies one-third of the total area of the plot. What is the length of the plot, in metres ?

1)	90 m	2)	80 m
3)	90 m	4)	120 m
5)	None of these

Answer : 120 m

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Q467.

The base of a triangle is 15 cm and height is 12 cm. The height of another triangle of double the area having the base 20 cm is :

1)	8 cm	2)	9 cm
3)	12.5 cm	4)	18 cm
5)	None of these

Answer : 18 cm
Explanation :

A₁= [(1/2) x 15 x 12]cm² = 90 cm² . A₂ = 2A₁ = 180 cm².

= (1/2) x 20 x h = 180 or h = 18 cm.

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Q468.

Each side of a rhombus is 26 cm and one of its diagonals is 48 cm long. The area of rhombus is :

1)	1600 cm2	2)	2400 cm2
3)	3600 cm2	4)	4800cm2
5)	None of these

Answer : 2400 cm2
Explanation :

AB = 26 cm and AC = (1/2) x 48 cm ; OA = 24 cm

OB² = AB² - OA² = (26)²- (24)² = (26 + 24) (26 - 24) = 100

or OB = 50 cm or BD = 2 x OB = (250) cm = 100 cm.

Therefore , Area = 1/2 x (AC x BD ) = [(1/2 ) x 48 x100 ] cm² = 2400 cm².

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Q469.

A rectangle has width a and length b. If the width is decreased by 20% and the length is increased by 10%, then what is the area of the new rectangle in percentage compared to 'ab' ?

1)	80%	2)	88%
3)	110%	4)	Can't be determined
5)	None of these

Answer : 88%
Explanation :

According to AB Methods:

New area = -20+10 - (20x10)/100 = -12%

So, required percentage

= (100 - 12 ) = 88%.

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Q470.

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required ?

1)	48	2)	56
3)	76	4)	88
5)	None of these

Answer : 88
Explanation :

We have, L = 20 ft and LB = 680 sq.ft

So, b = 680/20 = 34 ft.

Length of fencing (L+2B) = (20 + 68) ft = 88 ft.

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Previous 1 2...44 45 464748 49 50...62 63 Next

Mathmetics

Q461.

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age ?

Q462.

Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 yrs. old after 10yrs. ?

Q463.

The sum of the ages of a son and his father is 56yrs. After four yrs, the age of father will be three times that of the son . Find the age of the son ?

Q464.

The age of A's father is four times of his son. If 5 yrs ago, father's age was seven times of his son at that time. What is the present age of A's father ?

Q465.

A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:

Q466.

The length of a plot of land is 4 times it breadth. A playground measuring 1200 sq m occupies one-third of the total area of the plot. What is the length of the plot, in metres ?

Q467.

The base of a triangle is 15 cm and height is 12 cm. The height of another triangle of double the area having the base 20 cm is :

Q468.

Each side of a rhombus is 26 cm and one of its diagonals is 48 cm long. The area of rhombus is :

Q469.

A rectangle has width a and length b. If the width is decreased by 20% and the length is increased by 10%, then what is the area of the new rectangle in percentage compared to 'ab' ?

Q470.

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required ?

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