Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q191. |
|
| 1) | 17 years | 2) | 18 years |
| 3) | 19 years | 4) | 20 years |
| 5) | None of these | ||
Answer : 19 years
Explanation : The total age of 50 students = 50 X 16 = 800 yrs.
Explanation : The total age of 50 students = 50 X 16 = 800 yrs.
After admitted 10 new students ,total age become 60 X 16.5 = 990 yrs.
So, age of new students = 990 -800 = 190 yrs.
Thus, their average 190 /10 = 19 yrs.
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Q192. |
|
| 1) | Rs.5,425 | 2) | Rs.5,500 |
| 3) | Rs.5,446 | 4) | Rs.5,600 |
| 5) | None of these | ||
Answer : Rs.5,425
Explanation :
Explanation :
Total expenditure is = (55000 + 75400) = 62800
His saving is Rs. 2300
Total annual income = 62800 + 2300 = 65100
Monthly income = 65100 ÷ 12 = Rs. 5425
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Q193. | Two-fifth of a number is two more than one-third another number.If the sum of the two numbers is 16,what is their product ? |
| 1) | 40 | 2) | 48 |
| 3) | 54 | 4) | 60 |
| 5) | None of these | ||
Answer : 60
Explanation : Let, two numbers are x and y respectively.
Explanation : Let, two numbers are x and y respectively.
According to the questions, x + y = 16 ------- (I) and 2x/5 - y/3 = 2 -------- (II)
or 6x -5y = 30
Solving both equations , we get x = 10 and y = 6
So, their product = 10 X 6 = 60
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Q194. | The profit earned by selling an article for Rs.744 is double the loss incurred when the same article is sold for Rs.240. What would the selling price of the article if it is sold at 15% profit ? |
| 1) | Rs.472.20 | 2) | Rs.469.80 |
| 3) | Rs.468.20 | 4) | Rs.479.20 |
| 5) | None of these | ||
Answer : Rs.469.80
Explanation : Let, the C.P be Rs.x.
Explanation : Let, the C.P be Rs.x.
Then, according to the question, 744 - x = 2(x-240)
or 744 - x = 2x - 480
or 3x = 744 + 480 =1224
or x = 1224/3 = Rs.408
So, required S.P = 408 X (115/100 ) = Rs.469.20
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Q195. |
|
| 1) | 78 | 2) | 91 |
| 3) | 104 | 4) | 117 |
| 5) | None of these | ||
Answer : 91
Explanation : Let, two numbers are 13x and 13y respectively.
Explanation : Let, two numbers are 13x and 13y respectively.
So, 13x X 13y = 13 X 455
or xy = 35
Then, pairs of numbers are 35 = (1 X 35) , (5 x 7).
So, second pairs is considerable i.e. 13X5 = 65 and 13 X 7 = 91
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Q196. |
|
| 1) | 10 | 2) | 12 |
| 3) | 15 | 4) | 20 |
| 5) | None of these | ||
Answer : 10
Explanation : Let, two numbers are 5x and 5y respectively.
Explanation : Let, two numbers are 5x and 5y respectively.
So, 5x X 5y = 5 X 495
or 25xy = 5 X 495
or xy = 99
So, pairs of numbers are i.e. 99 = (1 X 99) and (9 x 11)
Therefore , the satisfy numbers are 9 x 5 = 45 and 11 x 5 = 55
So, the difference is 55 - 45 = 10.
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Q197. |
|
| 1) | 215 | 2) | 220 |
| 3) | 225 | 4) | 235 |
| 5) | None of these | ||
Answer : 225
Explanation : Given that, 45 H.C.F = L.C.M and
Explanation : Given that, 45 H.C.F = L.C.M and
H.C.F + L.C.M = 1150
or H.C.F + 45 H.C.F = 1150
or 46 H.C.F = 1150
or H.C.F = 1150/46 =25
So, L.C.M = 25 X 45 = 1125
Now, we can get 125 X x = 25 X 1125
or x = (25 X 1125) /125 = 225
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Q198. |
|
| 1) | 2825 | 2) | 2975 |
| 3) | 3025 | 4) | 3775 |
| 5) | None of these | ||
Answer : 3775
Explanation :
Explanation :
We know that,Sn = (1 + 2 + 3 + ... + 50 + 51 + 52 + ... + 100)/2 - (1 + 2 + 3 + ... + 50)/2
= 100 x (1 + 100) - 50 x (1 + 50) = (50 x 101) - (25 x 51)
= (5050 - 1275) = 3775.
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Q199. |
|
| 1) | 8 | 2) | 9 |
| 3) | 10 | 4) | 12 |
| 5) | None of these | ||
Answer : 10
Explanation :
Explanation :
4 a 3 |
9 8 4 } ==> a + 8 = b ==> b - a = 8
13 b 7 |
Also, 13 b7 is divisible by 11 (7 + 3) - (b + 1) = (9 - b)
(9 - b) = 0
or b = 9 (b = 9 and a = 1)
So, (a + b) = 10.
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Q200. |
|
| 1) | 1 | 2) | 2 |
| 3) | 3 | 4) | 4 |
| 5) | None of these | ||
Answer : 4
Explanation :
Explanation :
We, know that , Dividend = (divisor x Quotient )+Reminder
D = 5Q + 3
or D2 = (5Q + 3)2 = (25Q2 + 30Q + 9) = 5(5Q2 + 6Q + 1) + 4
On dividing D2 by 5, we get 4 as remainder.
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