Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
| Q121. | 
 | 
| 1) | 425 | 2) | 480 | 
| 3) | 520 | 4) | 625 | 
| 5) | None of these | ||
Answer : None of these  
Explanation : Let, the full mark be 100%.
Explanation : Let, the full mark be 100%.
A boy should requires marks to pass =  483 +117 = 600 
So, the full mark = 600  i.e. 100%
So, the required mark for a girl should = (600/40) x 35 = 525
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 View Answer| Q122. | 
Directions : Study the following graph carefully and answer the question below it. 	Percent Profit  earned by two companies A and B over the given years.  Ratio of expenditures of companies A and B in 2010 was 7 : 8 respectively. What was the ratio of their incomes in 2010 ?  | 
| 1) | 118 : 163 | 2) | 128 : 119 | 
| 3) | 121 : 147 | 4) | 163 : 118 | 
| 5) | None of these | ||
Answer : None of these 
Explanation :
Explanation :

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 View Answer| Q123. | 
Directions : Study the following graph carefully and answer the question below it. 	Percent Profit  earned by two companies A and B over the given years.  Total expenditure of company A in all the years together was Rs. 76.5 lakhs. What was the total income of the company in all the years together ? | 
| 1) | Rs. 98.5 lakhs | 2) | Rs. 89.3 lakhs | 
| 3) | Rs. 92.6 lakhs | 4) | Can’t be determined | 
| 5) | None of these | ||
Answer : Can’t be determined 
Explanation :
Explanation :
As the percentage profits are different for different years, we can not find the total income
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 View Answer| Q124. | 
Directions : Study the following graph carefully and answer the question below it. 	Percent Profit  earned by two companies A and B over the given years.  Expenditures of company B in 2007 and 2008 are Rs. 25 lakhs and Rs. 30 lakhs respectively. What was the total income of company B in 2007 and 2008 together ? | 
| 1) | Rs. 74.8 Lakhs | 2) | Rs. 85.5 Lakhs | 
| 3) | Rs. 68.4 Lakhs | 4) | Rs. 78.5 Lakhs | 
| 5) | None of these | ||
Answer : Rs. 85.5 Lakhs 
Explanation :
Explanation :

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 View Answer| Q125. | 
Directions : Study the following graph carefully and answer the question below it. 	Percent Profit  earned by two companies A and B over the given years.  If the income of company B in 2008 and 2009 were in the ratio 3 : 5 respectively, what was the ratio of the expenditure of that company in these two years ? | 
| 1) | 4 : 15 | 2) | 7 : 12 | 
| 3) | 9: 16 | 4) | Cannot determined | 
| 5) | None of these | ||
Answer : 9: 16 
Explanation :
Explanation :

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 View Answer| Q126. | 
 | 
| 1) | Rs.32 lakhs | 2) | Rs.46 lakhs | 
| 3) | Rs.16 lakhs | 4) | Cannot determined | 
| 5) | None of these | ||
Answer : Rs.32 lakhs 
Explanation :
Explanation :

Total expenditure of A and B in 2011 = 2 x 16 = 32 lakhs
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 View Answer| Q127. | Seven men and four boys can complete a work in 6 days. A man completes the double work than a boy. In how many days will 5 men and 4 boys complete the work ? | 
| 1) | 4 | 2) | 5 | 
| 3) | 6 | 4) | 8 | 
| 5) | None of these | ||
Answer : None of these  
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 View Answer| Q128. | 
Total number of children in six different schools and the percentage of girls are give bellow in the line-chart.   The numbers of boys in school Q is how much percentage (approx.) more or less than the numbers of girls in  the school  S  ? | 
| 1) | 140 | 2) | 142 | 
| 3) | 144 | 4) | 148 | 
| 5) | None of these | ||
Answer : 142 
Explanation : The numbers of boys in school Q = (3000 x 55/100) = 1650
Explanation : The numbers of boys in school Q = (3000 x 55/100) = 1650
The numbers of girls in  the school  S  = (2250 x 30/100) = 675 
So, different = 1650 - 675 = 975 
Therefore , required more % = (975/675) x 100 = 144 % (approx.)
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 View Answer| Q129. | 
Total number of children in six different schools and the percentage of girls are give bellow in the line-chart.   What is number of boys in school P and Q are more than girls in school of S and T ? | 
| 1) | 1475 more | 2) | 1655 less | 
| 3) | 1875 more | 4) | 1975 more | 
| 5) | None of these | ||
Answer : 1975 more  
Explanation : Total number of boys in school P and Q = [ (2500 x 60/100) + (3000 x 55/100) ] =1500 + 1650 = 3150.
Explanation : Total number of boys in school P and Q = [ (2500 x 60/100) + (3000 x 55/100) ] =1500 + 1650 = 3150.
Total number of girls in school S and T = [ (2250 x 30/100) +  (1250 x 40/100) ] = 675 + 500 = 1175
So, the different = 3150 -1175 = 1975
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 View Answer| Q130. | 
Total number of children in six different schools and the percentage of girls are give bellow in the line-chart.   What is the total number of boys in School S ? | 
| 1) | 675 | 2) | 1250 | 
| 3) | 1475 | 4) | 1575 | 
| 5) | None of these | ||
Answer : 1575 
Explanation : Given ,total numbers of children is 2250 and percentage of girls 30.
Explanation : Given ,total numbers of children is 2250 and percentage of girls 30.
So, percentage of boys =  2250 x 70/100 = 1575
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