Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q41. |
Directions: Study the following chart and table carefully to answer the questions that follow : Percentage breakup of employees working in various departments of an organization and the ratio of men to women in them. Percentage Breakup of Employees Total Number of employees = 1800 What is the number of men working in the Marketing department ? |
| 1) | 132 | 2) | 174 |
| 3) | 126 | 4) | 189 |
| 5) | None of these | ||
Answer : 189
View AnswerQ42. |
|
| 1) | Rs 20500 | 2) | Rs 22500 |
| 3) | Rs 22800 | 4) | Rs 23000 |
| 5) | None of these | ||
Answer : Rs 22500
View AnswerQ43. |
|
| 1) | 3800 | 2) | 4200 |
| 3) | 5000 | 4) | 5600 |
| 5) | None of these | ||
Answer : 5000
Explanation :
Explanation :
Difference = (35%of 250000) - (33% of 250000)
= (35% - 33%) of 250000 = 2% of 250000
= (2/100) x 250000 = 5000
View AnswerQ44. | Directions: Study the following bar Graph carefully and answer the questions given bellow :The Bar Diagram depicting the changes in the students strength of a college in four diffrent streams from 2007-08 to 2009-10. ![]() The Science students in the year 2009-10 is what percentage of the students in the same year ? |
| 1) | 35% | 2) | 37.5% |
| 3) | 42% | 4) | 45.5% |
| 5) | None of these | ||
Answer : 37.5%
Explanation : Stuents of all categories in the year 2009-10 =
Explanation : Stuents of all categories in the year 2009-10 =
500 + 600 + 250 +250 = 1600
Numbers of Science students = 600
So,required percentage = (600/1600) x 100 = 37.5%
View AnswerQ45. |
Directions: Study the following bar Graph carefully and answer the questions given bellow : The Bar Graph shows the percentage of three communities - A, Community B and Community C in a state during the years from 2004 to 2007. ![]() If the total population Community A in 2006 is 40,000 then what will be the population of Community B in the same year ? |
| 1) | 80,000 | 2) | 84,000 |
| 3) | 96,000 | 4) | Can't be determined |
| 5) | None of these | ||
Answer : 96,000
Explanation : The population of Community A is 25% i.e 40,000.
Explanation : The population of Community A is 25% i.e 40,000.
Then population of Community B = (40,000 /25) x 60 = 96,000
View AnswerQ46. |
Directions: Study the following bar Graph carefully and answer the questions given bellow : The Bar Graph shows the percentage of three communities - A, Community B and Community C in a state during the years from 2004 to 2007. ![]() If the total population in 2004 was 8,00,000 and in 2006 it was 9,00,000, by how much has the population of Community B increased in 2 years? |
| 1) | 25% | 2) | 50% |
| 3) | 75% | 4) | 80% |
| 5) | None of these | ||
Answer : 50%
Explanation : 45% of 800000 is 360000 and 60% of 900000 is 540000
Explanation : 45% of 800000 is 360000 and 60% of 900000 is 540000
So, the percentage of population increases = [(540000 - 360000)/360000] x 100 = 50%
View AnswerQ47. |
Directions: Study the following bar Graph carefully and answer the questions given bellow : The Bar Graph shows the percentage of three communities - A, Community B and Community C in a state during the years from 2004 to 2007. ![]() If the total population of the state in 2005 was 6 million, then the population of Community A was Answer (b). |
| 1) | 1800000 | 2) | 1950000 |
| 3) | 2100000 | 4) | 2250000 |
| 5) | None of these | ||
Answer : 2100000
Explanation :
Explanation :
In the year 2005, the population percentage of Community A ,B and C
= (35+55+15) % = 100%
So,the total population of Community A is (6,000,000)x(35/100) = Rs.2,100,000.
View AnswerQ48. |
Directions: Study the following bar Graph carefully and answer the questions given bellow : The Bar Graph shows the percentage of three communities - A, Community B and Community C in a state during the years from 2004 to 2007. ![]() If the total population of the state in 2004 was 5 lakhs, then the combined population of Community A and Community C in that year was |
| 1) | 180000 | 2) | 200000 |
| 3) | 250000 | 4) | 275000 |
| 5) | None of these | ||
Answer : 275000
Explanation : Total population = (500000 x 55)/100 = Rs.2,75,000.
Explanation : Total population = (500000 x 55)/100 = Rs.2,75,000.
View AnswerQ49. |
|
| 1) | 1:2 | 2) | 2:3 |
| 3) | 3:4 | 4) | 3:5 |
| 5) | None of these | ||
Answer : 2:3
Explanation : Community A : Community B = 30:45 or 2 : 3.
Explanation : Community A : Community B = 30:45 or 2 : 3.
View AnswerQ50. |
Direction: read the following the bar graph given below and give the answer: The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991-92 to 1998-99. : ![]() The foreign exchange reserves in 1996-97 were approximately what percent of the average foreign exchange reserves over the period under review ? |
| 1) | 80% | 2) | 85% |
| 3) | 90% | 4) | 125% |
| 5) | None of these | ||
Answer : 125%
Explanation :
Explanation :
The average of these 8 years =
1/8 (2640+3720+2520+3360+3120+4320+5040+3120) = US $ 3480 million
Foreign exchange reserves in 1996-97 = US $ 4320 million
So, required Percentage = [(4320/3480)x100] % = 125%
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