Mathmetics
 
									 		
									ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
									
									
									
									
						
				| Q1. | Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and given answers if . 	1) x > y				2) x y			3) x < y 	4) x y				5) x = y  or the relationship cannot be established 
 20x2 – x – 12 = 0 20y2 + 27y + 9 = 0 | 
				
					
Answer : 2 
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 View Answer| Q2. | Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and given answers if . 	1) x > y				2) x y			3) x < y 	4) x y				5) x = y     or the relationship cannot be established 
 
 	I.	x2 + 8x + 15 = 0	               II.	y2 + 13y + 42 = 0 | 
				
					
Answer : 1 
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 View Answer| Q3. | Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and given answers if . 	1) x > y				2) x y			3) x < y 	4) x y				5) x = y   or the relationship cannot be established 
 	I.	x2 - 4x + 3 = 0                       II.	y2 - 7y + 12 = 0 | 
				
					
Answer : 1 
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 View Answer| Q4. | Find the range of values of x for which x2 + 6x -27 > 0 | 
				
					
					
  
    | 1) | x < -9 or x < 3 | 2) | x < -9 or x > 3 | 
  
    | 3) | x > -9 or x > 3 | 4) | x > -9 or x < 3 | 
    | 5) | None of these | 
    
Answer : x > -9 or x > 3 
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 View Answer| Q5. | Find the range of values of x for which x2 + 6x -27 > 0 | 
				
					
					
  
    | 1) | x < -9 or x < 3 | 2) | x < -9 or x > 3 | 
  
    | 3) | x > -9 or x > 3 | 4) | x > -9 or x < 3 | 
    | 5) | None of these | 
    
Answer : x > -9 or x > 3 
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 View Answer| Q6. | Prove that, 8x - 15 - x2 > 0 for limited value of of x and also find the limits. | 
				
					
					
  
    | 1) | 3 > x < 5 | 2) | 3 < x > 5 | 
  
    | 3) | 3 < x < 5 | 4) | 3 > x > 5 | 
    | 5) | None of these | 
    
Answer : 3 < x < 5 
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 View Answer| Q7. | What shoul be real values of x, in the given expression  x2 - 2x - 3 > 0 | 
				
					
					
  
    | 1) | x > -1 or x > 3 | 2) | x < -1 or x > 3 | 
  
    | 3) | x > -1 or x < 3 | 4) | x > -1 or x < 3 | 
    | 5) | None of these | 
    
Answer : x < -1 or x > 3 
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 View Answer| Q8. | Which of the following values of x will satisfy the inequality x2 - 5x + 6 < 0 | 
				
					
					
  
    | 1) | 2< x < 3 | 2) | -2 < x < 2 | 
  
    | 3) | -3 < x < -2 | 4) | -3 < x < 2 | 
    | 5) | None of these | 
    
Answer : 2< x < 3 
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 View Answer| Q9. | Which of the following values of x will satisfy the inequality x2 -x - 6 > 0 ? | 
				
					
					
  
    | 1) | x < -2 or x > 3 | 2) | -2 < x < 3 | 
  
    | 3) | -3 < x < 2 | 4) | x> -2 or x < 3 | 
    | 5) | None of these | 
    
Answer : x < -2 or x > 3 
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 View Answer| Q10. | 
Directions : In each of the following questions two questions two equations I and II are given. You have to solve both the equation and give answer. 	1) if a <b			2) If a is less than or equal  b		3) if a is greater than or equal to b4) if a = b			5) if a > b 
 I. 6a2 + 5a + 1 = 0			II. 5b2 + 19b + 6 = 0 | 
				
					
					
  
    | 1) | 1 | 2) | 2 | 
  
    | 3) | 3 | 4) | 4 | 
    | 5) | None of these | 
    
Answer : None of these 
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