Quantitative aptitude Question for all banking Bank PO,Clerk,IBPS PO,Railway,SSC,PSUs,IAS,OAS ,C-SAT Exams

Mathmetics

ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams

Q11.	The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is:

1)	70 km/hr	2)	75 km/hr
3)	84 km/hr	4)	87.5 km/hr
5)	None of these

Answer : 87.5 km/hr
Explanation :

Let, the speed of two trains be 7x and 8x km/hr.

Then, 8x = (40/4)= 100

or x = (100 /8) = 12.5

So, Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.

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Q12.	Excluding stoppages, the speed of a bus is 60 kmph and including stoppages, it is 50 kmph. For how many minutes does the bus stop per hour?

1)	9 min	2)	10 min
3)	12 min	4)	20 min
5)	None of these

Answer : 10 min
Explanation :

Due to stoppages, it covers 10km less.

Time taken to cover 9 km = [ (10/60) x 60 ] min = 10 min.

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Q13.	The speed of a bus increases by 2 km after every one hour. If the distance travelling in the first one hour was 35 km. what was the total distance travelled in 12 hours ?

1)	428 km	2)	502 km
3)	552 km	4)	586 km
5)	None of these

Answer : 552 km
Explanation :

Given that distance travelled in 1st hour = 35 km

and speed of the bus increases by 2 km after every one hour

Hence distance travelled in 2nd hour = 37 km

Hence distance travelled in 3rd hour = 39 km

Total Distance Travelled = [35 + 37 + 39 + ... (12 terms)]

This is an Arithmetic Progression(AP) with

first term, a=35, number of terms,n = 12 and common difference, d=2.

The sequence a , (a + d), (a + 2d), (a + 3d), (a + 4d), . . . is called an Arithmetic Progression(AP)

where a is the first term and d is the common difference of the AP

Sum of the first n terms of an Arithmetic Progression(AP),Sn=n/2[2a+(n−1)d]

where n = number of terms

Hence, [35+37+39+... (12 terms)]=S12=12/2[2�35+(12−1)2]=6[70+22]=6�92=552

Hence the total distance travelled = 552 km

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Q14.	Walking 6/7th of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance ?

1)	1 hr	2)	1 hr 12 min
3)	1 hr 36 min	4)	2 hrs
5)	None of these

Answer : 1 hr 12 min
Explanation :

Let distace = 1 km , seed= 1 kmph So, time taken = 1/1= 1hr

New speed = 6/7 of usual speed

Speed and time are inversely proportional.

Hence new time = 7/6 of usual time

Hence, 7/6 of usual time - usual time = 12 minutes

=> 1/6 of usual time = 12 minutes

=> usual time = 12 x 6 = 72 minutes = 1 hour 12 minutes

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Q15.	A man covered a certain distance at some speed. If he had moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. What is the the distance in km ?

1)	32	2)	36
3)	40	4)	48
5)	None of these

Answer : 40

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Q16.	A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

1)	120 km	2)	180 km
3)	205 km	4)	224 km
5)	None of these

Answer : 224 km
Explanation :

we know that , Distance = speed x time

Let time taken to travel the first half = x hr

then time taken to travel the second half = (10 - x) hr

Distance covered in the the first half = 21x

Distance covered in the the second half = 24(10 - x)

But distance covered in the the first half = Distance covered in the the second half

=> 21x = 24(10 - x) => 21x = 240 - 24x => 45x = 240 ⇒x=16/3

Hence Distance covered in the the first half = 21x=21�16/3 = 7�16=112 km

Total distance = 2�112 = 224 km

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Q17.	Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour ?

1)	8	2)	9
3)	10	4)	12
5)	None of these

Answer : 10
Explanation :

Speed of the bus excluding stoppages = 54 kmph

speed of the bus including stoppages = 45 kmph

Loss in speed when including stoppages = 54 - 45 = 9kmph

=> In 1 hour, bus covers 9 km less due to stoppages

Hence, time that the bus stop per hour = time taken to cover 9 km

=distance/speed=9/54 hour =1/6 hour = 60/6 min =10 min

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Mathmetics

Q11.

The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is:

Q12.

Excluding stoppages, the speed of a bus is 60 kmph and including stoppages, it is 50 kmph. For how many minutes does the bus stop per hour?

Q13.

The speed of a bus increases by 2 km after every one hour. If the distance travelling in the first one hour was 35 km. what was the total distance travelled in 12 hours ?

Q14.

Walking 6/7th of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance ?

Q15.

A man covered a certain distance at some speed. If he had moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. What is the the distance in km ?

Q16.

A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

Q17.

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour ?

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