Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q11. |
|
| 1) | 12 years | 2) | 14 years |
| 3) | 18 years | 4) | 20 years |
| 5) | None of these | ||
Answer : 20 years
Explanation :
Explanation :
Let, the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
or 54 - x = 5x - 30
or 6x = 84
or x = 14.
Son's age after 6 years = (x + 6) = 20 years.
View AnswerQ12. |
|
| 1) | 14 years | 2) | 18 years |
| 3) | 20 years | 4) | 22 years |
| 5) | None of these | ||
Answer : 22 years
Explanation :
Explanation :
Let, the son's present age be x years.
Then, man's present age = (x + 24) years.
or (x + 24) + 2 = 2(x + 2)
or x + 26 = 2x + 4
or x = 22.
View AnswerQ13. |
|
| 1) | 24 | 2) | 27 |
| 3) | 40 | 4) | Can't be determined |
| 5) | None of these | ||
Answer : 24
Explanation :
Explanation :
Let, the present ages of Susant and Alok be 5x years and 4x years respectively.
Then, (5x - 3)/(4x - 3) = 11 /9
or 9(5x + 3) = 11(4x + 3)
or 45x + 27 = 44x + 33
or 45x - 44x = 33 - 27
or x = 6.
Alok's present age = 4x = 24 years.
View AnswerQ14. |
|
| 1) | 7 yrs | 2) | 8 yrs |
| 3) | 9 yrs | 4) | 10 yrs |
| 5) | None of these | ||
Answer : 10 yrs
Explanation :
Explanation :
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 or x = 5.
Hence, B's age = 2x = 10 years.
View AnswerQ15. |
|
| 1) | 14 years | 2) | 19 years |
| 3) | 33 years | 4) | 38 years |
| 5) | None of these | ||
Answer : 14 years
Explanation :
Explanation :
Let, the son's present age be x years. Then, (38 - x) = x
or 2x = 38.
or x = 19.
Therefore. son's age 5 years back (19 - 5) = 14 years.
View AnswerQ16. |
|
| 1) | 4 years | 2) | 8 years |
| 3) | 10 years | 4) | 12 years |
| 5) | None of these | ||
Answer : 4 years
Explanation :
Explanation :
Let, the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20 or x = 4.
So, the age of the youngest child , x = 4 years.
View AnswerQ17. |
|
| 1) | 2 times | 2) | 3 times |
| 3) | 4 times | 4) | 5 times |
| 5) | None of these | ||
Answer : 2 times
Explanation :
Explanation :
Let, Ronit's present age be x years.
Then, father's present age = (x + 3x) years = 4x years.
(4x+8) = (x + 2) 5/2
or 8x + 16 = 5x + 40
or 3x = 24 or x = 8.
Hence, required ratio = (4x+16) / (x+16) = 48/24 =2.
View AnswerQ18. |
|
| 1) | 10 yrs | 2) | 12 yrs |
| 3) | 16 yrs | 4) | 20 yrs |
| 5) | None of these | ||
Answer : 20 yrs
Explanation :
Explanation :
Let, age of Ajaya 10 years back was x years.
Then, Sachin’s age 10yrs. was 2x yrs.
So, 2x + 20 = 40
or x = 10 yrs.
So, the present age of Ajay = 10 +10 = 20 yrs.
View AnswerQ19. |
|
| 1) | 6 yrs | 2) | 10 yrs |
| 3) | 12 yrs | 4) | 20 yrs |
| 5) | None of these | ||
Answer : 12 yrs
Explanation :
Explanation :
Let the age of the son and father be x yrs. and y yrs. respectively.
Then , x + y = 56 yrs. ---- I
After 4yrs. age of both will be 56 + 8 = 64yrs.
But according to hypothesis,
or 3 (x + 4) = y + 4 or 3x + 12 = y + 4 or 3x - y = - 8 -------- II
Solving both equations, we get x = 12.
SHORT-CUT METHOD:
[64/3+1] - 4 = 12 yrs
View AnswerQ20. |
|
| 1) | 28 | 2) | 32 |
| 3) | 40 | 4) | 45 |
| 5) | None of these | ||
Answer : 40
Explanation :
Explanation :
Let age of son be x.Then father's age be 4x.
Five years ago age of boths are x - 5 and 4x - 5 respectly.
or 7 (x - 5 ) = 4x - 5
or 7x - 35 = 4x - 5 or 7x - 4x = 30 or 3x = 30 or x = 10
Therefore, Father's age = 10 x 4 = 40 years
SHORT-CUT METHOD :
Father's age = [5 x(7-1)] /(4-1) x 4 = 40 yrs
View Answer
