Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q11. |
|
| 1) | 140 | 2) | 150 |
| 3) | 152 | 4) | 159 |
| 5) | None of these | ||
Answer : 150
Explanation :
Explanation :
The 3-digit number divisible by 6 are : 102, 108, 114,... , 996
It is an A.P. series where a = 102, d = 6 and l = 996
Let, the number of terms be n. Then tn = 996.
or a + (n - 1) d = 996
or 102 + (n - 1) x 6 = 996
or 6 x (n - 1) = 894
or (n - 1) = 149
or n = 150
So, number of terms = 150.
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Q12. |
|
| 1) | 2 | 2) | 3 |
| 3) | 4 | 4) | 6 |
| 5) | None of these | ||
Answer : 4
Explanation :
Explanation :
90 = 10 x 9
Clearly, 653xy is divisible by 10, so y = 0
Now, 653x0 is divisible by 9.
So, (6 + 5 + 3 + x + 0) = (14 + x) is divisible by 9. So, x = 4.
Hence, (x + y) = (4 + 0) = 4.
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Q13. |
|
| 1) | 6 only | 2) | 6 and 12 both |
| 3) | 12 only | 4) | by 18 only |
| 5) | None of these | ||
Answer : 6 and 12 both
Explanation : (6n2 + 6n) = 6n (n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.
Explanation : (6n2 + 6n) = 6n (n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.
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Q14. | What would be the unit digit of the following expressions. |
| 1) | 4 | 2) | 6 |
| 3) | 7 | 4) | 9 |
| 5) | None of these | ||
Answer : 7
Explanation : We know that, any digit multiply four times, that product's unit digit will be same digit.
Explanation : We know that, any digit multiply four times, that product's unit digit will be same digit.
So,125/4 =31 quotient and 1 reminder and 127/4 = 31 divisor and 3 reminder.
Now, (123)1 + (234)3 = 3 + 4 = 7
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Q15. | A number, when divided by 135, the reminder is 45. If the same number is divided by 27, what would be the reminder ? |
| 1) | 15 | 2) | 18 |
| 3) | 21 | 4) | Data Inadequate |
| 5) | None of these | ||
Answer : 18
Explanation : We know that, Dividend = (Divisor x Quotient) + Reminder.
Explanation : We know that, Dividend = (Divisor x Quotient) + Reminder.
So, Dividend = (135 x Quotient) + 45
Or Dividend = [ (27 x 5 x Quotient )+ (27 x 1 +18)]
When above Dividend is divided by 27, 18 will be reminder.
Short-Cut Method:
If the second divisor is a factor of the first divisor, then you just divide the second divisor with reminder.
i.e. (R1/d2) = R2
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Q16. |
|
| 1) | 24 | 2) | 38 |
| 3) | 42 | 4) | 48 |
| 5) | Non of these | ||
Answer : 38
Explanation :
Explanation :
Let, the numbers be x and x + 2.
Then, (x + 2)2 - x2 = 84
or 4x + 4 = 84 or 4x = 80
or x = 20. The required sum = x + (x + 2) = 2x + 2 = 42.
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Q17. |
|
| 1) | 235 | 2) | 253 |
| 3) | 273 | 4) | 352 |
| 5) | None of these | ||
Answer : 253
Explanation :
Explanation :
Let, the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred's digits is smaller than the unit's digit.
Hence, required number = 253.
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Q18. |
|
| 1) | 18 | 2) | 24 |
| 3) | 42 | 4) | 81 |
| 5) | None of these | ||
Answer : 24
Explanation :
Explanation :
Let, the ten's and unit digit be x and y respectively.
So, xy = 8 and the number be 10x+y
When 18 is added, the number be 10x+ y +18.
Then, 10x + y + 18 = 10 y + x
or 9x - 9y = -18 x - y = - 2
We know that (x+y)2=( x-y)2 + 4xy = (-2)2 + 4 x 8 =36
or x+y = 6
By solving we get x = 2 and y = 4
Thus, the number is 24.
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Q19. |
|
| 1) | 3 | 2) | 5 |
| 3) | 10 | 4) | 11 |
| 5) | None of these | ||
Answer : 11
Explanation :
Explanation :
Let, the ten's digit be x and unit's digit be y.
Then, number = 10x + y.
Number obtained by interchanging the digits = 10y + x.
(10x + y) + (10y + x) = 11(x + y), which is divisible by 11
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Q20. |
|
| 1) | 4 | 2) | 8 |
| 3) | 12 | 4) | 14 |
| 5) | None of these | ||
Answer : 8
Explanation :
Explanation :
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let, ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
or 9x = 36
or x = 4.
So, required difference = (2x + x) - (2x - x) = 2x = 8.
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